If $K +\frac{1}{K} + 2 = 0 $ and K <

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If $K +\frac{1}{K} + 2 = 0 $ and K < 0, then what is the value of $ K^{11}+\frac{1}{K^4}$ ?

Options:

-2

-1

-17

Correct Answer:

Explanation:

$K +\frac{1}{K} + 2 = 0 $

$K +\frac{1}{K} = -2 $

Put k = -1

$ -1^{11}+\frac{1}{-1^4}$ = 0