Let $f(x)=-x^3+a x^2+b x+5 \sin x \cos x$ be a decreasing function on the set R. Then, a and b satisfy
Answer & explanation
Correct answer: option 2
We have,
$f(x)=-x^3+a x^2+b x+\frac{5}{2} \sin 2 x$
$\Rightarrow f'(x)=-3 x^2+2 a x+b+5 \cos 2 x$
For f(x) to be decreasing on R, we must have
$f'(x)<0$ for all $x \in R$
$\Rightarrow -3 x^2+2 a x+b+5 \cos 2 x<0$ for all $x \in R$
$\Rightarrow -3 x^2+2 a x+b+5<0$ for all $x \in R$
$\Rightarrow 3 x^2-2 a x-b-5>0$ for all $x \in R$
$\Rightarrow 4 a^2-4 \times 3(-b-5)<0$ [∵ Disc < 0]
$\Rightarrow a^2+3 b+5<0$