The minimum value of f(x) = |2x − 1| is

The correct answer is Option (2) → 0

The modulus is never negative:

    \(|2x-1| \ge 0 \text{ for all } x\)

and the value 0 is reached:

    \(2x-1=0\)
    \(x=\frac{1}{2},\quad f\left(\frac{1}{2}\right)=0\)

So the minimum value is 0.