Practicing Success
The value of the determinant $\begin{vmatrix}a+b & b+c & c+a\\c & a & b\\1 & 1 & 1\end{vmatrix}$ is : |
0 -1 1 2 |
0 |
The correct answer is Option (1) → 0 $Δ=\begin{vmatrix}a+b & b+c & c+a\\c & a & b\\1 & 1 & 1\end{vmatrix}$ $R_1→R_1+R_2$ $\begin{vmatrix}a+b+c & a+b+c & a+b+c\\c & a & b\\1 & 1 & 1\end{vmatrix}$ $R_1$ is identical to $R_2$ $⇒Δ=0$ |