The corrdinates of the point where the line $\frac{x-3}{2}=\frac{y-4}{-3}=\frac{z-1}{5}$ crosses XY plane is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\left(\frac{13}{5},\frac{23}{5}, 0 \right)$
$\frac{x-3}{2}=\frac{y-4}{-3}=\frac{z-1}{5}=λ$
so $x=2λ+3,y=4-3λ,z=5λ+1$
at crossing of xy plane
$z = 0⇒λ=-\frac{1}{5}$
so $x=\frac{13}{5},y=\frac{23}{5},z=0$