A cell of e.m.f 4 V and internal resistance $0.2 \Omega$ is connected to $1.8 \Omega$ (ohm) external resistance. The potential difference across the terminal of the cell will be:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 3.6 V
Now,
Current (I) = $\frac{V}{R}$ [By ohm's law]
$=\frac{4}{1.8+0.2}$
$=2A$
∴ Voltage across resistance = $2×1.8=3.6V$