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Angle between tangents to the curve $y=x^2-5 x+6$ at the points (2, 0) and (3, 0) is: |
0° 45° 60° 90° |
90° |
The correct answer is Option (4) - 90° $y=x^2-5x+6$ $\frac{dy}{dx}=2x-5$ so $m_1=\left.\frac{dy}{dx}\right]_{x=2}=-1$ $m_2=\left.\frac{dy}{dx}\right]_{x=2}=1$ $m_1m_2=-1$ so both are at 90° to each other |
