Angle between tangents to the curve $y=x^2-5 x+6$ at the points (2, 0) and (3, 0) is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) - 90°
$y=x^2-5x+6$
$\frac{dy}{dx}=2x-5$
so $m_1=\left.\frac{dy}{dx}\right]_{x=2}=-1$
$m_2=\left.\frac{dy}{dx}\right]_{x=2}=1$
$m_1m_2=-1$
so both are at 90° to each other