The intercepts cut off by the planes \(2x+y-z=5\) are
Answer & explanation
Correct answer: option 2
Given \(2x+y-z=5\)
$\Rightarrow \frac{2x}{5} + \frac{y}{5} - \frac{z}{5} = 1$
$ \Rightarrow \frac{x}{5/2} + \frac{y}{5} - \frac{z}{5} = 1$
Compare this equation with standard form
$\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1$
$ \Rightarrow a = \frac{5}{2} , b = 5 , c = -5$