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The value of \(\frac{3 sin 15°}{cos 75°}\) + \(\frac{cos 20°}{sin 70°}\) is: |
-1 1 4 0 |
4 |
\(\frac{3 sin 15°}{cos 75°}\) + \(\frac{cos 20°}{sin 70°}\) = 3 + 1 = 4 (because if A + B = 90°, then \(\frac{sin A}{secB}\) = 1) |
