The value of (3 sin 15°)/(cos 75°) + (cos 20°)/(sin 70°) is:

\(\frac{3 sin 15°}{cos 75°}\) + \(\frac{cos 20°}{sin 70°}\)

= 3 + 1 = 4

(because if A + B = 90°, then \(\frac{sin A}{secB}\) = 1)