Practicing Success
The relation $R=\{(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)\}$ on the set $A=\{1,2,3\}$ is : |
Reflexive but not Symmetric Reflexive but not Transitive Symmetric and Transitive Neither Symmetric nor Transitive |
Reflexive but not Symmetric |
$R=\{(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)\}$ $A=\{1,2,3\}$ for every $a \in A \quad(a, a)$ is present in $R$ i.e. $(1,1)(2,2)(3,3)$ are present hence its reflexive. for every $(a, b) \in R,(b, a) \in R$ This is not satisfied here eg: $(1,2) \in R$ but $(2,1) \notin R$ Hence it is not symmetric for $(a, b),(b, c) \in R \quad(a, c)$ must be preselect to be transitive relation in this case $(1,2)$ and $(2,3) \in R$ $(1,3) \in R$ as well So this is transitive as wall Reflexive but not symmetric |