According to Bohr's theory, the angular momentum of an electron revolving in the second orbit of the hydrogen atom will be
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \( h/\pi \)
Bohr's quantisation condition says that the angular momentum of the electron in the \( n \)th orbit is an integral multiple of \( h/2\pi \).
\( \displaystyle L = \frac{n h}{2\pi} \)
\( \displaystyle L = \frac{2h}{2\pi} = \frac{h}{\pi} \)