According to Bohr's theory, the angular momentum of an electron revolving in the second orbit of the hydrogen atom will be
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\frac{h}{\pi}$
Given:
For Bohr’s model, angular momentum is quantized as
$L = n \frac{h}{2\pi}$
For second orbit (n = 2):
$L = 2 \frac{h}{2\pi} = \frac{h}{\pi}$
∴ The angular momentum of the electron in the second orbit is $\frac{h}{\pi}$.