Practicing Success
Fg and Fe represent the gravitational and electrostatic forces respectively between two electrons situated at a distance of 10 cms. The ratio of Fg/Fe is of the order of |
1043 1036 10-43 10-36 |
10-43 |
$\frac{\mathrm{F}_{\mathrm{g}}}{\mathrm{F}_{\mathrm{e}}}=\frac{\frac{\text { Gme me }}{\mathrm{r}^2}}{\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{e}^2}{\mathrm{r}^2}}$ $=\frac{6.67 \times 10^{-11} \times\left(9 \times 10^{-31}\right)^2}{9 \times 10^9 \times\left(1.6 \times 10^{-19}\right)^2}=10^{-43}$ |