If $A_1, A_2, .....A_n $ are any n events, then
Answer & explanation
Correct answer: option 3
For any two events A and B, we have
$P(A ∪ B) = P(A) + P(B) - P(A ∩ B)$
$⇒ P(A ∩ B) ≤ P(A) + P(B)$
Using principle of mathematical induction it can be easily proved that
$P\left(\bigcup\limits_{i=1}^nA_i\right) ≤ \sum\limits^{n}_{i=1} P(A_i)$