Match List I with List II
Choose the correct answer from the options given below: |
A-IV, B-III, C-I, D-II A-IV, B-I, C-III, D-II A-IV, B-III, C-II, D-I A-I, B-II, C-III, D-IV |
A-IV, B-III, C-I, D-II |
The correct answer is option 1. A-IV, B-III, C-I, D-II.
Let us go through each salt and its corresponding van't Hoff factor: \((NH_4)_2Fe(SO_4)_2.6H_2O \longrightarrow 2NH_4^+ + Fe^{2+} + 2SO_4^{2-}\) Since, the number of ions formed is five. Thus the van't Hoff factor, \(i = 5\). B. Blue vitriol: The formula of blue vitriol is \(CuSO_4 . 5H_2O\). Blue vitriol dissociates to two ions: \(CuSO_4.5H2O \longrightarrow Cu^{2+} + SO_4^{2-}\) Since, the number of ions formed is two. Thus the van't Hoff factor, \(i = 2\). C. Lime slake: The formula of lime slake is \(Cu(OH)_2\). Lime slake dissociates into three ions: \(Cu(OH)_2 \longrightarrow Cu^{2+} + 2OH^-\) Since, the number of ions formed is three. Thus the van't Hoff factor, \(i = 3\). D. Alum:he formula of alum is \(K_2SO_4Al_2(SO_4)_3.24H_2O\). alum dissociates into eight ions: \(K_2SO_4Al_2(SO_4)_3.24H_2O \longrightarrow 2K^+ + 2Al^{3+} + 4SO_4^{2-}\) Since, the number of ions formed is eight. Thus the van't Hoff factor, \(i = 8\). Thus the correct match is option 1. A-IV, B-III, C-I, D-II. |