If p-2 q=3 and p q=5, then what is the value of ≤ft(p^3-8 q^3) ?

If $p-2 q=3$ and $p q=5$

What is the value of $\left(p^3-8 q^3\right)$ 

If x - y  = n

then, $x^3 - y^3$ = n³ + 3 × n × xy

$\left(p^3-8 q^3\right)$  = 3³ + 3 × 3 × 5 × 2

$\left(p^3-8 q^3\right)$ = 27 + 90

$\left(p^3-8 q^3\right)$  = 117