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A p-type semiconductor in which doping was done of the order of 5.65 x \( { 10}^{ 6} \) atoms, the net charge on the sample becomes what? |
1.6 x 5.65 x \( { 10}^{ 25} \) - 1.6 x \( { 10}^{ 19} \) zero 1.6 x \( { 10}^{ 19} \) |
zero |
Whether it is a p-type semiconductor or an n-type semiconductor, the total charge is always zero i.e. it is electrically neutral. |
