An aqueous solution has molality 11.11. What is the mole fraction of solute in solution?

0.167 0.833 0.40 0.60

0.167

Molality 11.11 means 11.11 moles of solute are present in 1000 g of water. nA = \(\frac{1000}{18}\)  mole fraction of solute, XB = \(\frac{n_B}{n_B + n_A}\) = \(\frac{11.11}{11.11 + \frac{1000}{18}}\) = 0.167