In a transistor circuit, when the base current is increased by 50 μA, keeping collector voltage fixed at 2 volt, the collector current increase by 1.0 mA. The current amplification factor of the transistor will be:
Answer & explanation
Correct answer: option 2
$β=\frac{ΔI_c}{ΔI_b}=\frac{1×10^{-3}}{50×10^{-6}}=20$