In a school, 60% of the number of students are boys and the rest are girls. If 20% of the number of boys failed and 65% of the number of girls passed the examination, then the percentage of the total number of students who passed is:
Answer & explanation
Correct answer: option 4
60% = \(\frac{3}{5}\) , 80% = \(\frac{4}{5}\) & 65% = \(\frac{13}{20}\)
Let total number of students = 100x
Number of boys = 100x × \(\frac{3}{5}\) = 60x
Number of girls = 100x – 60x = 40x
Number of passed boys = 60x × \(\frac{4}{5}\) = 48x
Number of passed girls = 40x × \(\frac{13}{20}\) = 26x
Total passed students = 48x + 26x = 74x
Required percentage = \(\frac{74x}{100x}\) × 100 = 74%