Practicing Success
The differential equation representing the family of curves y = m(x – d) where m and d are arbitrary constants, is |
\( \frac{d y}{d x}=0 \) \( \frac{d^2 y}{d x^2}=0 \) \( x \frac{d^2 y}{d x^2}+y=0 \) \( x \frac{d^2 y}{d x^2}-y=0 \) |
\( \frac{d^2 y}{d x^2}=0 \) |
$y = m(x – d)$ Differentiating w.r.t.x, we get, $\frac{dy}{dx}=m(x-d)⇒m$ as $m(1-0)=m$ $\frac{d^2y}{dx^2}=0$, this is required differential equation. Option B is correct. |