Hybridization of central metal ion in [Fe(NH3)4(en)]2+ will be
Answer & explanation
Correct answer: option 3
In [Fe(NH3)4(en)]2+
x + 4(0) + 1(0) = 2
x = 2
26Fe: [Ar]4s23d6
Fe2+: [Ar]3d6
| ↑↓ | ↑ | ↑ | ↑ | ↑ |
In presence of strong field ligand,
| ↑↓ | ↑↓ | ↑↓ |
six donor atoms will use d2sp3 hybrid orbitals and hybridization of central metal ion will be d2sp3.