The base of a hemispherical bowl has a circumference of 132 cm. Find the capacity of the bowl.(Use $π =\frac{22}{7}$)

19404 cm³

Circumference of base of hemisphere bowl is = 2 × π × r

ATQ,

2 × \(\frac{22}{7}\) × r = 132

r = 21 cm

Now, Capacity of hemispherical bowl =  \(\frac{2}{3}\)π r³

= \(\frac{2}{3}\) ×  \(\frac{22}{7}\) × 21³

= 2 × 22 × 21²

= 19404 cm³