If $f(x)=x^3+3x^2+10x+2\sin x$, then range of the function is

(0, 2) (− ∞, ∞) (− ∞, 0) (0, ∞)

(− ∞, ∞)

$f(x) = x^3 + 3x^2 +10x + 2\sin x ; −∞ < x^3 + 3x^2 +10x < ∞$ as a cubic polynomial. So, $−∞ < x^3 + 3x^2 +10x + 2\sin x < ∞$