What is the oxidation state of Pt in $(PtF_5)_4$?

+5

The correct answer is Option (2) → +5

In $(\text{PtF}_5)_4$​:

• Fluorine has an oxidation state of –1
• Each Pt is bonded to 5 F atoms

So, for one $\text{PtF}_5$​ unit:

$\text{Oxidation state of Pt} + 5(-1) = 0$

$\text{Oxidation state of Pt} = +5$

The tetrameric nature $(\text{PtF}_5)_4$​ does not change the oxidation state of Pt.