What is the oxidation state of Pt in $(PtF_5)_4$?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → +5
In $(\text{PtF}_5)_4$:
- Fluorine has an oxidation state of –1
- Each Pt is bonded to 5 F atoms
So, for one $\text{PtF}_5$ unit:
$\text{Oxidation state of Pt} + 5(-1) = 0$
$\text{Oxidation state of Pt} = +5$
The tetrameric nature $(\text{PtF}_5)_4$ does not change the oxidation state of Pt.