Let A and B be 3 × 3 matrices of real numbers, where A is symmetric, B is skew-symmetric, and $(A + B) (A-B) = (A-B) (A + B)$ if $(AB)^T =(-1)^n AB$, then
Answer & explanation
Correct answer: option 4
We have,
$(A + B) (A-B) = (A - B) (A + B)$
$⇒AB = BA$ ...(i)
Now, $(AB)^T=(-1)^n AB$
$⇒ B^T A^T =(-1)^n AB$
$⇒(-B) A=(-1)^n AB$ [∵ $B^T-B$ and $A^T = A$]
$⇒-BA=(-1)^nBA$ [Using (i)]
$⇒(-1)^n=-1$
⇒ n is an odd natural number