The number of equivalence relation on the set $\{1,2, 3\}$ containing (1, 2) and (2, 1) is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 2
Given set $A = \{1, 2, 3\}$ and the relation contains $(1,2)$ and $(2,1)$.
For an equivalence relation, it must be reflexive, symmetric, and transitive.
Since $(1,2)$ and $(2,1)$ are in $R$, transitivity implies $(1,1)$ and $(2,2)$ must also be in $R$.
Hence, $1$ and $2$ belong to the same equivalence class $\{1,2\}$.
The third element $3$ may either:
- remain separate as $\{3\}$, giving partition $\{\{1,2\}, \{3\}\}$
- or join them, giving partition $\{\{1,2,3\}\}$
Thus, the number of such equivalence relations = 2.
Final Answer: 2