Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Differential Equations

Question:

The solution of the differential equation $\frac{dy}{dx}=-\frac{x}{y}$ is :

Options:

$x^2+y^2=2C,$ where C is constant of integration.

$x-y^2=2C,$ where C is constant of integration.

$x^2+y=2C,$ where C is constant of integration.

$x^2-y^2=2C,$ where C is constant of integration.

Correct Answer:

$x^2+y^2=2C,$ where C is constant of integration.

Explanation:

The correct answer is Option (1) → $x^2+y^2=2C,$ where C is constant of integration.

$\frac{dy}{dx}=-\frac{x}{y}$

so $\int ydy=\int -xdx$

$\frac{y^2}{2}=-\frac{x^2}{2}+C$

so $x^2+y^2=2C$