Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: D and F Block Elements

Question:

Which one of the following ions exhibits the highest magnetic moment?

Options:

Cu2+

Ti3+

Ni2+

Mn2+

Correct Answer:

Mn2+

Explanation:

The correct answer is option 4. \(Mn^{2+}\).

The magnetic moment of an ion is a measure of the strength of its magnetic field. It is determined by the number of unpaired electrons in the ion's d-orbital.

The ions $Cu^{2+}, Ti^{3+},\text{ and } Ni^{2+}$ all have unpaired electrons in their d-orbitals, but $Mn^{2+}$ has the highest number of unpaired electrons (5). Therefore, $Mn^{2+}$ has the highest magnetic moment.

Here is a table of the magnetic moments of the ions in Bohr magnetons :

Ion

Number of

unpaired electrons

Magnetic moment (μ)

Cu2+

1

\(\mu = \sqrt{1(1+2)} = \sqrt{3} = 1.73 BM\)

Ti3+

1

\(\mu = \sqrt{1(1+2)} = \sqrt{3} = 1.73 BM\)

Ni2+

2

\(\mu = \sqrt{2(2+2)} = \sqrt{8} = 2.83 BM\)

Mn2+

5

\(\mu = \sqrt{5(5+2)} = \sqrt{35} = 5.92 BM\)

As you can see, \(Mn^{2+}\) has the highest magnetic moment of the four ions.