Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

If Rm is the radius of moon orbit round the earth, am the acceleration of moon towards the centre of earth, and Re the radius of earth. Then am is equal to (if g is acceleration due to gravity on the surface of earth)

Options:

$\left(\frac{R_e}{R_m}\right) g$

$\left(\frac{R_m}{R_e}\right) g$

$\left(\frac{R_m}{R_e}\right)^2 g$

$\left(\frac{R_e}{R_m}\right)^2 g$

Correct Answer:

$\left(\frac{R_e}{R_m}\right)^2 g$

Explanation:

$\mathrm{g}=\frac{\mathrm{GM}_{\mathrm{e}}}{\mathrm{R}_{\mathrm{e}}^2}$          ..........(1)

$\mathrm{a}_{\mathrm{m}}=\frac{\mathrm{GM}_{\mathrm{e}}}{\mathrm{R}_{\mathrm{m}}^2}$       ..........(2)

$\frac{(2)}{(1)}, \frac{a_m}{g}=\frac{\frac{\mathrm{GM}_e}{\mathrm{R}_{\mathrm{m}}^{\mathrm{e}}}}{\frac{\mathrm{GM}_{\mathrm{e}}}{\mathrm{R}_{\mathrm{e}}^2}}=\frac{\mathrm{R}_{\mathrm{e}}^2}{\mathrm{R}_{\mathrm{m}}^2} ; \mathrm{a}_{\mathrm{m}}=\left(\frac{\mathrm{R}_{\mathrm{e}}}{\mathrm{R}_{\mathrm{m}}}\right)^2 \mathrm{~g} \mathrm{f}$