Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

$\lim\limits_{\alpha \rightarrow \pi / 4} \frac{\sin \alpha-\cos \alpha}{\alpha-\frac{\pi}{4}}=$

Options:

$\frac{1}{\sqrt{2}}$

2

$\sqrt{2}$

1

Correct Answer:

$\sqrt{2}$

Explanation:

$\lim\limits_{\alpha \rightarrow \pi / 4} \frac{\sin \alpha-\cos \alpha}{\alpha-\pi / 4}$

Using L'Hopital's Rule

so $\lim\limits_{\alpha \rightarrow \pi / 4} \frac{\cos \alpha+\sin \alpha}{1}=\frac{2}{\sqrt{2}}=\sqrt{2}$

Hence (3) is the correct answer.