The degree of the differential equation $\left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^{\frac{3}{2}} = \frac{d^2y}{dx^2}$ is

2

The correct answer is Option (3) → 2 ##

The given differential equation is $\left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^{\frac{3}{2}} = \frac{d^2y}{dx^2}$

$\left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^3 = \left( \frac{d^2y}{dx^2} \right)^2$

The order of the differential equation is 2.

The degree of the differential equation is 2.