The degree of the differential equation $\left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^{\frac{3}{2}} = \frac{d^2y}{dx^2}$ is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 2 ##
The given differential equation is $\left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^{\frac{3}{2}} = \frac{d^2y}{dx^2}$
$\left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^3 = \left( \frac{d^2y}{dx^2} \right)^2$
The order of the differential equation is 2.
The degree of the differential equation is 2.