The value of $tan(cos^{-1}x)$ is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{\sqrt{1-x^2}}{x}$
$\tan(\cos^{-1}x)$
Using pythagoras theorem
so $\tan(\cos^{-1}x)$
$=\tan θ=\frac{\sqrt{1-x^2}}{x}$
The value of $tan(cos^{-1}x)$ is :
Correct answer: option 2
The correct answer is Option (2) → $\frac{\sqrt{1-x^2}}{x}$
$\tan(\cos^{-1}x)$
Using pythagoras theorem
so $\tan(\cos^{-1}x)$
$=\tan θ=\frac{\sqrt{1-x^2}}{x}$