Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electric Charges and Fields

Question:

Options:

a

b

c

d

Correct Answer:

b

Explanation:

$F = \frac{kQ^2}{r^2} = \frac{9\times 10^9 \times (10^{-6})^2}{2^2} = 2.25\times 10^{-3}N$