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Find the value of secθ - tanθ, if secθ + tanθ = √5. |
5 $5\frac{1}{5}$ $\frac{\sqrt{5}}{5}$ $\sqrt{5}$ |
$\frac{\sqrt{5}}{5}$ |
We know that, $\sec^2θ\, - tan^2θ$ = 1 (secθ - tanθ)(secθ + tanθ) = 1 (secθ - tanθ)$\sqrt{5}$ = 1 (secθ - tanθ) = $\frac{1}{\sqrt{5}}$ = $\frac{\sqrt{5}}{5}$ |
