AB = 80 m, BC = 60 m
DF = 50 m, GE = 50 m
HE = 100m
Area of region ACDF is:
Answer & explanation
Correct answer: option 1
area of ΔACE = = \(\frac{1}{2}\) × AC × EH = \(\frac{1}{2}\) × 100 × 100 = 5000 m2
area of ΔEFD = \(\frac{1}{2}\) × DF × EG = \(\frac{1}{2}\) × 50× 50 = 1250 m2
Area of region ACDF = area of ΔACE - area of ΔEFD
= 5000 - 1250 = 3750 m2