The value of ∫limits_-2^2≤ft(a x^3+b x+c) d x depends on

$I=\int\limits_{-2}^2\left(a x^3+b x\right) d x+c \int\limits_{-2}^2 d x=0+c . 4=4 c$

(∵ ax³ + bx is an odd function of x).

Hence (2) is the correct answer.