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What is the $27^{th}$ term of the A.P 3, 7, 11, ................ ? |
111 107 103 130 |
107 |
This is an arithmetic progression, where first term (a) is 3, an there is a common difference (d) = +4 nth term for an AP generally is a + (n - 1)d In this case it is 3 + (n-1).4 = 3 + 4n - 4 = 4n - 1 So, 27th term = 4 x 27 - 1 = 107 |
