A cesium photocell, with a steady potential difference of 60 V across, is illuminated by a bright point source of light 50 cm away. When the same light is placed 1 m away, the photoelectrons emitted from the cell -

Are one quarter as numerous

d₁ = 50 cm

d₂ = 1m = 100 cm

$d_1=2d_1(I∝\frac{1}{d^2})$

I₂ = I₁/4

$n_{ph_2}=\frac{n_{ph_1}}{4}$

$n_{e_2}=\frac{n_{e_1}}{4}$