A bag contains 5 black, 3 white and 2 red balls. Three balls are drawn in succession. What is the probability that the first ball is red, the second ball is black and the third ball is white?
Answer & explanation
Correct answer: option 1
We have,
A bag contains 5 black, 3 white and 2 red balls
Total number of balls = 5 + 3 + 2 = 10
Among three balls the probability that the first ball is red, the second ball is black and the third ball is white =
= \(\frac{5}{10}\) × \(\frac{3}{9}\) × \(\frac{2}{8}\)
= $\frac{1}{24}$