A bag contains 5 black, 3 white and 2 red balls. Three balls are drawn in succession. What is the probability that the first ball is red, the second ball is black and the third ball is white?

$\frac{1}{24}$

We have,

A bag contains 5 black, 3 white and 2 red balls

Total number of balls = 5 + 3 + 2 = 10

Among three balls the probability that the first ball is red, the second ball is black and the third ball is white =

= \(\frac{5}{10}\) × \(\frac{3}{9}\) × \(\frac{2}{8}\)

= $\frac{1}{24}$