Find the integral \(\int\frac{( { x }^{ 2 } + 4x - 5)}{x+5}dx\)
Answer & explanation
Correct answer: option 1
\(\int\frac{( { x }^{ 2 } + 4x - 5)}{x+5}dx=\int\frac{(x+5)(x-1)}{(x+5)}dx\)
$=\int x-1\,dx$
$=\frac{ { x }^{ 2 } }{2} - x+c$
Find the integral \(\int\frac{( { x }^{ 2 } + 4x - 5)}{x+5}dx\)
Correct answer: option 1
\(\int\frac{( { x }^{ 2 } + 4x - 5)}{x+5}dx=\int\frac{(x+5)(x-1)}{(x+5)}dx\)
$=\int x-1\,dx$
$=\frac{ { x }^{ 2 } }{2} - x+c$