Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Options:

a

b

c

d

Correct Answer:

b

Explanation:

$\text{Electric Field } \vec{E} = -\frac{dV}{dr} = \frac{k}{r^2} \hat{r}$

$ \vec{E} =  \frac{k}{r^3} \vec{r}$

$|\vec{r}| = 7 $

$\Rightarrow \vec{E} =  \frac{k}{343} (2\hat{i} + 3\hat{j} + 6\hat{k})$