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Physics
Electrostatic Potential and Capacitance
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$\text{Electric Field } \vec{E} = -\frac{dV}{dr} = \frac{k}{r^2} \hat{r}$
$ \vec{E} = \frac{k}{r^3} \vec{r}$
$|\vec{r}| = 7 $
$\Rightarrow \vec{E} = \frac{k}{343} (2\hat{i} + 3\hat{j} + 6\hat{k})$