Practicing Success
If x+y+z = 7 x2 + y2 + z2 = 85 x3 + y3 + z3 = 913 then \(\sqrt[3]{xyz}-4\) is equal to: |
4 2 0 8 |
0 |
(x+y+z)2 = x2 + y2 + z2 + 2(xy +yz+zx) 49 = 85 + 2(xy +yz+zx) xy +yz+zx = -18 x3 + y3 + z3 - 3xyz = (x+y+z) (x2 + y2 + z2 - xy - yz - zx) 913 - 3xyz = (7)(85 -(-18)) 3xyz = 192 xyz = 64 \(\sqrt[3]{xyz}-4\) = \(\sqrt[3]{64}-4\) = 0 |