The sum of four consecutive integers is 1290. The greatest of them is?
Answer & explanation
Correct answer: option 4
Let the 1st number be x
So, the numbers are x, x+1, x+2, x+3
According to the question:
x + x+1 + x+2 + x+3 = 1290
4x + 6 = 1290
4x = 1284
x = 321
The greatest number is x + 3. So, the greatest number is 321 + 3 = 324