The sum of four consecutive integers is 1290. The greatest of them is?

321 322 323 324

324

Let the 1st number be x So, the numbers are x, x+1, x+2, x+3  According to the question: x + x+1 + x+2 + x+3 = 1290 4x + 6 = 1290 4x = 1284 x = 321 The greatest number is x + 3. So, the greatest number is 321 + 3 = 324