An AC voltage source of variable angular frequency ω and fixed amplitude Vo is connected in series with a capacitance C and an electric bulb of resistance R (inductance zero). When ω is increased then,
Answer & explanation
Correct answer: option 2
Impedance is $ Z = \sqrt{R^2+ \frac{1}{\omega^2 C^2}}$
When frequency increases Z decreases.
$\Rightarrow I = \frac{V}{Z}$ Increases.
As more current flows through the circuit with increased frequency, the bulb glows brighter.