Practicing Success
The rank of the matrix $A =\begin{bmatrix}1&2&3\\3&6&9\\1&2&3\end{bmatrix}$, is |
1 2 3 none of these |
1 |
We observe that $|A|=0$ and every square sub-matrix of order 2 is singular. But, A is a non-null matrix. Therefore, $r (A) = 1$. |