If cos(A-B) = $\frac{\sqrt{3}}{2}$ and s - CUETMOCK

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If cos(A-B) = $\frac{\sqrt{3}}{2}$ and secA2, 0°≤ A≤ 90°,0° B≤ 90°, then what is the measure of B?

Options:

60°

0°

30°

90°

Correct Answer:

30°

Explanation:

We know ,

cos 30º = \(\frac{√3}{2}\)

& sec 60º = 2

So , A = 60º

So , ( A - B ) = 30º

60º - B = 30º

B = 30º

CUET Questions