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In Bohr's model, the atomic radius of the first orbit is $r_0$, then the radius of the third orbit is |
$\frac{r_0}{9}$ $r_0$ $9 r_0$ $3 r_0$ |
$9 r_0$ |
$r_n \propto n^2$ $\Rightarrow \frac{r_3}{r_1} = \frac{3^2}{1^2} = 9$ $\Rightarrow r_3 = 9 r_0$ |
