In Bohr's model, the atomic radius of the first orbit is $r_0$, then the radius of the third orbit is
Answer & explanation
Correct answer: option 3
$r_n \propto n^2$
$\Rightarrow \frac{r_3}{r_1} = \frac{3^2}{1^2} = 9$
$\Rightarrow r_3 = 9 r_0$
In Bohr's model, the atomic radius of the first orbit is $r_0$, then the radius of the third orbit is
Correct answer: option 3
$r_n \propto n^2$
$\Rightarrow \frac{r_3}{r_1} = \frac{3^2}{1^2} = 9$
$\Rightarrow r_3 = 9 r_0$