Relation between equilibrium constant and standard potential of the cell under standard conditions is represented by ____. |
$E°_{cell}=\frac{2.303\, RT}{F}\log K_c$ $E°_{cell}=\frac{2.303\, RT}{nF}\log K_c$ $E°_{cell}=\frac{2.303}{nF}\log K_c$ $E°_{cell}=\frac{2.303\, R}{nF}\log K_c$ |
$E°_{cell}=\frac{2.303\, RT}{nF}\log K_c$ |
The correct answer is Option (2) → $E°_{cell}=\frac{2.303\, RT}{nF}\log K_c$ The relation between the standard cell potential (E°cell) and the equilibrium constant (Kc) under standard conditions is derived from the Nernst equation: The fundamental equations are: ΔG° = −nF E°cell ΔG° = −RT ln K Where n = number of electrons transferred F = Faraday constant R = gas constant T = temperature in Kelvin Equating the two equations: $\Delta G^\circ = -RT \ln K = -n F E^\circ_\text{cell}$ $E^\circ_\text{cell} = \frac{RT}{nF} \ln K$ Converting ln to log10: $E^\circ_\text{cell} = \frac{2.303 RT}{nF} \log K$ |