CUET Preparation Today
Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(II), (B)-(I), (C)-(III), (D)-(IV) (A)-(I), (B)-(II), (C)-(IV), (D)-(III) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
(A)-(II), (B)-(I), (C)-(III), (D)-(IV) |
The correct answer is Option (2) → (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
(A) Kolbe's Reaction → (II) Salicylic acid Also called Kolbe-Schmitt reaction. Sodium phenoxide reacts with $CO_2$ under pressure to introduce a $-COOH$ group ortho to $-OH$, forming salicylic acid.
(B) Reimer-Tiemann Reaction → (I) Salicylaldehyde Phenol treated with $CHCl_3$ and $NaOH$ forms $-CHO$ group at the ortho position via dichlorocarbene intermediate.
(C) Williamson Synthesis → (III) Ethyl methyl ether Alkoxide ion reacts with an alkyl halide (SN2 reaction) to form ethers like $CH_3-O-C_2H_5$.
(D) Cumene Process → (IV) Phenol Oxidation of cumene (isopropylbenzene) followed by acid cleavage of cumene hydroperoxide yields phenol and acetone.
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