Which one of the following functions is not one-one? |
$f:(-1,∞) → R$ given by $f (x) = x^2 + 2x$ $g:(1,∞) → R$ given by $g(x) = e^{x^3-3x+2}$ $h: R→ R$ given by $h(x) = 2^{x(x-1)}$ $\phi: (-∞, 0) → R$ given by $\phi(x)=\frac{x^2}{x^2+1}$ |
$h: R→ R$ given by $h(x) = 2^{x(x-1)}$ |
We have, $f(x) = x^2 + 2x, x ∈ (-1, ∞)$ $⇒f'(x)=2(x+1)>0$ for all $x ∈(-1,∞)$ ⇒ f(x) is one-one. It is given that $g(x) = e^{x^3-3x+2}, x ∈(1,∞)$ $∴g'(x)=e^{x^3-3x+2} × 3 (x^2-1) > 0$ for all $x ∈(1,∞)$ ⇒ g(x) is one-one. We have, $⇒ h(x) = 2^{x(x-1)}$ $⇒ h' (x) = 2^{x (x-1)} (2x-1)$ $⇒h' (x) > 0$ for all $x >\frac{1}{2}$ and $h' (x) <0$ for all $x <\frac{1}{2}$ ⇒ h(x) is not one-one. $∵\phi(x)=\frac{x^2}{x^2+1}$ for all $x ∈ (-∞, 0)$ $∴\phi'(x)=\frac{(x^2+1)2x-x^2×2x}{(x^2+1)^2}$ $⇒f'(x)=\frac{2x}{(x^2+1)^2}<0$ for all $x∈ (-∞, 0)$ $⇒\phi(x)$ is one-one. |